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Question

In a screw gauge, 5 complete rotations of circular scale give \1.5 mm reading on linear scale. Circular scale has 50 divisions. The least count of the screw gauge is x×10y(mm). Find (x+y).

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Solution

Pitch: In a screw gauge, the pitch is defined as the distance travelled in one rotation of screw.
Linear distance covered in 5 rotations =1.5 mm
Pitch =1.55=0.3 mm
There are 50 circular scale divisions.
Then, least count =0.350=0.006
It can be written as 6×103
Compare it with x×10y(mm).
we get,
x+y=63=3
Final Answer: 3

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