Question

In a screw gauge, the main scale division is $1\text{mm}$ and there are $100$ divisions on circular scale. The least count of screw gauge is (Pitch $=1\text{mm}$)

Answer 1

Least count of a screw gauge is given by,

$\text{L.C.}=\frac{\text{Pitch}}{\text{Number of circular scale divisions}}$

$=\frac{1\text{mm}}{100}$

$=0.01\text{mm}$