In a season a football team played 60 matches. They won 18, lost 20 and the rest
were draws. Find the following ratios:
(a) number of matches won to number of matches drawn,
(b) number of matches won to other matches

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Solution

Dear Student,

$T o t a l m a t c h e s p l a y e d = 60 m a t c h e s w o n = 18 m a t c h e s l o s t = 20 m a t c h e s d r a w n = 60 - 18 - 20 = 22 a) r a t i o o f m a t c h e s w o n t o m a t c h e s d r a w n = \frac{18}{22} = \frac{9}{11} b) r a t i o o f m a t c h e s w o n t o o t h e r m a t c h e s = \frac{18}{60 - 18} = \frac{18}{42} = \frac{3}{7}$
Regards,

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