In a semiconductor diode, the barrier potential offers opposition to only
A
Majority carriers in both regions
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B
Minority carriers in both regions
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C
Free electrons in the n-region
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D
Holes in the p-region
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Solution
The correct option is A Majority carriers in both regions When a semiconductor diode is formed, a depletion layer is formed across its junction. This depletion layer has negative charge in p-type crystal and positive charge in n-type crystal, thus acts as a potential barrier for charge carriers.
In p-region, holes are majority carriers (electrons are minority carriers) and in n- region electrons are majority carriers (holes are minority carriers). When an electron (majority carrier) from n-region, tries to cross the junction, the negative charge of the barrier (in p-region) opposes the electron (whereas helps the hole) and electron is stopped by this barrier's negative plate. Same happens with a hole in p-region. Hence, the potential barrier offers opposition to majority carriers in both regions.