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Question

In a sequence, if Sn is the sum of the first n terms and Sn−1 is the sum of the first (n-1) terms, then the nth term is

A
Sn2
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B
SnSn1
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C
Sn+1Sn
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D
Sn+1Sn1
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Solution

The correct option is B SnSn1
Let a be the first term and d be their common difference of the AP.
Then, Sum to n terms of an AP =n2(2a+(n1)d)
Clearly, we get Sn by adding the nth term to the sum Sn1
So Sn=Sn1+Tn

nth term is SnSn1

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