In a series, if $T_{n} = 3 - n$ , then $S_{5} =$

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Solution

The correct option is C 0
Given, $T_{n} = 3 - n$
So, $T_{1} = 3 - 1 = 2$
$T_{2} = 3 - 2 = 1$
$T_{3} = 3 - 3 = 0$
$T_{4} = 3 - 4 = - 1$
$T_{5} = 3 - 5 = - 2$
Required $S_{5} =$ Sum of these $5$ terms $= 2 + 1 + 0 - 1 - 2 = 0$

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