Question

In a series L-C-R circuit the voltage across the resistance , capacitance and inductance is 10 V each. If capacitance is short circuited, the voltage across the inductance will be:

• A. $10V$
• B. $10\sqrt{3}V$
• C. $10/\sqrt{2}V$
• D. $20V$

Answer 1

Answer: (C)

$10/\sqrt{2}V$

The voltages across all the three components are equal, so the impedance will be the same.

$R=X_L$

The current is given as,

$I=\frac{V}{\sqrt{R^2+{\left(X_L\right)}^2}}$

$I=\frac{10}{R\sqrt{2}}$

The potential drop across inductor is given as,

$V_L=I{X}_L$

$V_L=IR$

$V_L=\frac{10}{\sqrt{2}}V$