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Question

In a series L-C-R circuit voltage and the frequency of the main supply are 220 V and 50 Hz respectively. On taking out the capacitor from the circuit the current lags behind the voltage by 30o. On taking out the inductor from the circuit the current leads the voltage by 30o. The power dissipated in the L-C-R circuit is:(if R = 200 Ω

A
305 W
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B
210 W
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C
Zero
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D
242 W
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Solution

The correct option is D 242 W
The given circuit is under resonance as XL=XC Hence, power dissipated in the circuit is
P=V2R=242W.

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