In a series L-C-R circuit voltage and the frequency of the main supply are 220 V and 50 Hz respectively- On taking out the capacitor from the circuit the current lags behind the voltage by 30- On taking out the inductor from the circuit the current leads the voltage by 30- The power dissipated in the L-CR circuit is-if R -200 -A- 305 WB- 210 WC- 242 WD- Zero

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Standard XII

Physics

Transistor as an Amplifier

In a series L...

Question

In a series L-C-R circuit voltage and the frequency of the main supply are 220 V and 50 Hz respectively. On taking out the capacitor from the circuit the current lags behind the voltage by $30^{o}$ . On taking out the inductor from the circuit the current leads the voltage by $30^{o}$ . The power dissipated in the L-C-R circuit is:(if R = 200 $Ω$

305 W

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210 W

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Zero

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242 W

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Solution

The correct option is D 242 W
The given circuit is under resonance as $X_{L} = X_{C}$ Hence, power dissipated in the circuit is
$P = \frac{V^{2}}{R} = 242 W$ .

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The correct option is D 242 WThe given circuit is under resonance as XL=XC Hence, power dissipated in the circuit is P=V2R=242W.

The correct option is D 242 W
The given circuit is under resonance as $X_{L} = X_{C}$ Hence, power dissipated in the circuit is
$P = \frac{V^{2}}{R} = 242 W$ .