Question

In a series $LCR$ circuit, current in the circuit is $11\text{A}$ when the applied voltage is $220\text{V}$. Voltage across the capacitor is $200\text{V}$. If the value of resistor is $20\Omega$, then the voltage across the unknown inductor is

• A. $Zero$
• B. $200\text{V}$
• C. $20\text{V}$
• D. $100\text{V}$

Answer 1

The correct option is B $200\text{V}$

Given:
$R=20\Omega ,V_C=200\text{V},i_{net}=11\text{A},V_{net}=220\text{V}$

Now, $V_R=i_{net}\times R=11\times 20=220\text{V}$

From phasor diagram,

$V_{net}^2=V_R^2+(V_L-V_C{)}^2$

$\Rightarrow {220}^2={220}^2+(V_L-V_C{)}^2$

$\Rightarrow V_L=V_C=200\text{V}$

Hence, option $\left(B\right)$ is correct.