Given:
Resistance in series LCR circuit, R = 300 Ω
Capacitance in series LCR circuit, C = 20 μF= 20 × 10−6 F
Inductance in series LCR circuit, L = 1 Henry
RMS value of voltage, εrms = 50 V
Frequency of source, f = 50/ Hz
Reactance of the inductor (XL) is given by,
XL= = 2fL
XL = 2 = 100
Reactance of the capacitance is given by,
=
XC =
XC =
(a) Impedance of an LCR circuit is given by,
RMS value of current is given by,
Irms =
Irms =
(b) Potential across the capacitor is given by,
VC = Irms × XC
VC = 0.1 × 500 = 50 V
Potential difference across the resistor is given by,
VR = Irms × R
VR = 0.1 × 300 = 30 V
Potential difference across the inductor is given by,
VL = Irms × XL
VL= 0.1 × 100 = 10 V
R.M.S potential = 50 V
Net sum of all the potential drops = 50 V + 30 V + 10 V = 90 V
Sum of the potential drops > RMS potential applied