In a series LCR circuit X L-10- X C-10- R -6- The power factor of the circuit is-

The correct option is A 1 cosθ=Rz=R√(R^2+0)=1 cosθ=1 ...

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Standard XII

Physics

RMS Value

In a series L...

Question

In a series LCR circuit $X_{L} = 10 Ω; X_{C} = 10 Ω; R = 6 Ω$ . The power factor of the circuit is:

1

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\frac{\sqrt{3}}{2}

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1 / 2

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none of these

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Solution

The correct option is A $1$
$cos θ = \frac{R}{z} = \frac{R}{\sqrt{R^{2} + 0}} = 1 cos θ = 1$

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In a series LCR circuit XL=10Ω;XC=10Ω;R=6Ω. The power factor of the circuit is:

The correct option is A 1cosθ=Rz=R√R2+0=1cosθ=1

In a series LCR circuit $X_{L} = 10 Ω; X_{C} = 10 Ω; R = 6 Ω$ . The power factor of the circuit is:

The correct option is A $1$
$cos θ = \frac{R}{z} = \frac{R}{\sqrt{R^{2} + 0}} = 1 cos θ = 1$