In a series circuit, power of is dissipated from a source of . The power factor of the circuit is . In order to bring the power factor to unity, a capacitor of value is added in series to the and . Taking the value of as , then the value of is __________.
Step 1: Given data
Power,
Source voltage,
Frequency,
Power factor,
Step 2: To find
We have to find the value of in the equation
Step 3: Finding Impedance,
We know, power is given by,
Where is rms current and is the impedance of the circuit.
Substituting the values,
Step 4: Finding resistance, inductive reactance and capacitive reactance
Also,
Impedance,
Since the power factor is unity,
Step 5: Finding capacitance and hence
Since, , we get
The value of is