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Standard XII

Physics

RLC Circuit

In a series r...

Question

In a series resonant circuit, the AC voltage across resistance R, inductor L and capacitor C are 5 V, 10 V and 10 V respectively. The AC voltage applied to the circuit will be

10 V

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25 V

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5 V

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20 V

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Solution

The correct option is B 5 V
Given, $V_{R} = 5 V, V_{L} = 10$ and $V_{C} = 10 V$
In the MR circuit, the AC voltage applied to the circuit will be
$V = \sqrt{V_{R}^{2} + (V_{L} - V_{C})^{2}}$
$= \sqrt{(5)^{2} + (10 - 10)^{2}}$
$= 5 V$

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In a series resonant circuit, the AC voltage across resistance R, inductor L and capacitor C are 5 V, 10 V and 10 V respectively. The AC voltage applied to the circuit will be

The correct option is B 5 VGiven, VR=5V,VL=10 and VC=10VIn the MR circuit, the AC voltage applied to the circuit will be V=√V2R+(VL−VC)2=√(5)2+(10−10)2=5V

The correct option is B 5 V
Given, $V_{R} = 5 V, V_{L} = 10$ and $V_{C} = 10 V$
In the MR circuit, the AC voltage applied to the circuit will be
$V = \sqrt{V_{R}^{2} + (V_{L} - V_{C})^{2}}$
$= \sqrt{(5)^{2} + (10 - 10)^{2}}$
$= 5 V$