In a series resonant LCR circuit, the voltage across R is 100volts and R=1kΩ with C=2μF. The resonant frequency is 200rad/s. At resonance the voltage across L is
A
4 x 10−3V
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B
2.5 x 10−2V
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C
40V
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D
250V
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Solution
The correct option is B250V The resonant angular frequency , ω=1√LC
L=1ω2C=12002×2×10−6=12.5H
At resonance , impedance Z=R so the current in the circuit is
I=VZ=VR=1001000=0.1A
Voltage across inductor, VL=IXL=IωL=0.1×200×12.5=250V