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Question

In a series, Tn=2n+5, find S4.

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Solution

Tn=2n+5
T1=2(1)+5=7;T22(2)+=9
T3=2(3)+5=11;T4=2(4)+5=12
S4=T1+T2+T3+T4=7+9+11+13=40

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