In a series LCR circuit L-1 H- C-6-25 - F and R-1 - Its quality factor is-

Given, L=1 H ; C=6.25 μ F ; R=1 Ω In a series LCR circuit, Quality factor (Q)=1R√(LC) Q=11√(16.25× 10^ 6)=400 lt;!–td border: 1px solid #ccc;br mso d ...

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Standard XII

Physics

Impedance Triangle

In a series L...

Question

In a series $LCR$ circuit $L = 1 H, C = 6.25 μ F$ and $R = 1 Ω$ . Its quality factor is-

400

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200

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25

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125

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Solution

The correct option is A $400$
Given,
$L = 1 H; C = 6.25 μ F; R = 1 Ω$

In a series $LCR$ circuit,

Quality factor $(Q) = \frac{1}{R} \sqrt{\frac{L}{C}}$

$Q = \frac{1}{1} \sqrt{\frac{1}{6.25 \times 10^{- 6}}} = 400$

 Hence, $(A)$ is the correct answer.

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In a series LCR circuit L=1 H, C=6.25 μ F and R=1 Ω. Its quality factor is-

The correct option is A 400Given, L=1 H ; C=6.25 μ F ; R=1 Ω In a series LCR circuit, Quality factor (Q)=1R√LC Q=11√16.25×10−6=400  Hence, (A) is the correct answer.

In a series $LCR$ circuit $L = 1 H, C = 6.25 μ F$ and $R = 1 Ω$ . Its quality factor is-