wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a set of four numbers the first three are in GP and the last three are in AP with common difference 6. If the first number is the same as the fourth then third number of this set is

A
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2
Let the last three numbers in A.P with common difference 6 are:
q,q+6,q+12
Hence, the four numbers are:- p,q,q+6,q+12
Given, first and fourth number are equal.
p=q+12
and first three numbers p,q,q+6 are in G.P.
q2=p(q+6)
q2=(q+12)(q+6) [p=q+12]
q2=q2+18q+72
18q=72
q=4
So, Third number =q+6=4+6=2
Option B is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arithmetic Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon