In a simple machine, whose velocity ratio is 30, a load of 2400 N is lifted by an effort of 150 N and a load of 3000 N is lifted by an effort of 180 N. Find the law of machine -
A
P=0.50W+144
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B
P=0.60W+25
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C
P=0.05W+144
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D
P=0.05W+30
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Solution
The correct option is DP=0.05W+30 law of machine is p=mw+cp= effort
w=load
here P1=150N,W1=2400N
P2=180NW2=3000N150=2400m+C−180=3000m+C1,30=600m on m=0.05