In a simple pendulum mass of bob is $m$ and effecting length is $L$ . Work done on the pendulum in one complete oscillation in gravitational field of earth is

\frac{1}{4} m g L

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\frac{1}{2} m g L

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Zero

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m g L

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Solution

The correct option is B Zero
It will be zero in complete one oscillation due to gravitational force because displacement of bob will be zero.

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