Question

In a simultaneous throw of a pair of a dice, the probability of getting a total more than $7$ is

• A. $\frac{7}{12}$
• B. $\frac{5}{36}$
• C. $\frac{5}{12}$
• D. $\frac{7}{36}$

Answer 1

The correct option is C $\frac{5}{12}$

Total number of outcomes $=6\times 6=36$
Favourable outcomes $=\left\{\right(2,6),(6,2),(3,5),(5,3),(4,4),(3,6),(6,3),(4,5),(5,4),(4,6),(6,4),(5,5),(5,6),(6,5),(6,6\left)\right\}$
$\therefore$ Probability of getting a total more than 7
$=\frac{15}{36}=\frac{5}{12}$