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Question
In a simultaneous throw of a pair of dice, find the probability of getting:
A doublet
A doublet
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Solution
Given :Two dice are thrownHere, 2 dice are thrown, so possible outcomes are :(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)Hence total number of outcomes =36Let E= event of getting a doubt∴ No. of favourable outcomes =6{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}and total no of outcomes =36∴P(E)=6/36=1/6
Two dice are thrown
Here, 2 dice are thrown, so possible outcomes are :
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
Hence total number of outcomes =36
Let E= event of getting a doubt
∴ No. of favourable outcomes =6{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}
and total no of outcomes =36
∴P(E)=6/36=1/6
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