Question

In a simultaneous throw of a pair of dice, find the probability of getting a total more than $10$.

• A. $\frac{1}{12}$
• B. $\frac{1}{2}$
• C. $\frac{1}{9}$
• D. $\frac{1}{6}$

Answer 1

The correct option is A $\frac{1}{12}$

Two dice were thrown.

Total outcomes: $36$

Number of outcomes which makes sum of more than $10$ are: $3\to \left\{\right(5,6),(6,5),(6,6\left)\right\}$

Required probability:

$P=\frac{3}{36}=\frac{1}{12}$