Question

In a simultaneous throw of two dice, find P (A or B) if A denotes the event 'a total of 11 and B denotes the event an odd number on each die.

• A. $\frac{11}{36}$
• B. $\frac{1}{4}$
• C. $\frac{5}{18}$
• D. $\frac{1}{6}$

Answer 1

The correct option is A $\frac{11}{36}$

Getting total of 11 B : Getting odd number one each die

A = [(6, 5), (5, 6)]

B = [(1, 1), (1, 3), (1, 5), (3, 1), (3, 3), (3, 5), (5, 1), (5, 3), (5, 5)]

$P\left(A\right)=\frac{2}{36},P\left(B\right)=\frac{9}{36},P(A\cap B)=0$


$\therefore Requiredprobability$

$=P\left(A\right)+P\left(B\right)-P(A\cap B)$

$=\frac{2}{36}+\frac{9}{36}-0$

$=\frac{11}{36}$