Question

In a simultaneous throw of two dice, what is the probability of getting a total of 10 or 11 ?

• A. $\frac{7}{12}$
• B. $\frac{5}{36}$
• C. $\frac{1}{6}$
• D. $\frac{1}{4}$

Answer 1

The correct option is B $\frac{5}{36}$

Let A denotes the event of getting a total of 10 and B denotes the event of getting a total of 11.

Total outcomes = $6\times 6$

A= {(5,5),(6,4),(4,6)}

n(A) = $3$

$\therefore$ p(A) = $\frac{3}{36}$

B={(6,5),(5,6)}

n(B) = 2

$\therefore$ p(B)= $\frac{2}{36}$

$\therefore$ p(A or B) = p(A) + p(B)

= $\frac{3}{36}+\frac{2}{36}$

= $\frac{5}{36}$

Option B is correct.