Question

In a simultaneous throw of two dice, what is the probability of getting a total of or $11$?

• A. $\frac{1}{4}$
• B. $\frac{1}{6}$
• C. $\frac{7}{12}$
• D. $\frac{5}{36}$

Answer 1

Answer: (D)

$\frac{5}{36}$

In a simultaneous throw of two dice we have n(S)=(6$\times$6)=36
Let E = event of getting a total of 10 or 11 = {(4, 6), (5, 5), (6, 4), (5, 6), (6, 5)}
$\therefore P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{5}{36}$