Question

In a simultaneous throw of two dice, what is the probability of getting a total of $7$?

• A. $\frac{1}{6}$
• B. $\frac{1}{4}$
• C. $\frac{2}{3}$
• D. $\frac{3}{4}$

Answer 1

The correct option is A $\frac{1}{6}$

We know that in a simultaneous throw of two dice n(S)=$6\times 6=36$
Let E= event of getting a total of 7={(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}
$\therefore P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{6}{36}=\frac{1}{6}$