Question

In a simultaneous toss of two coins, find the probability of getting two tails.

• A. $\frac{1}{2}$
• B. $\frac{1}{4}$
• C. $\frac{3}{4}$
• D. $\frac{1}{3}$

Answer 1

The correct option is B $\frac{1}{4}$

Let us denote the head of the coins by H and

the tail of the coins by $T$.

Then the possible events are $HT,TH,HH,TT.$

So, the total number of events i.e space $=4$.

The number of favourable events (i.e TT) =1

$\therefore$ The probability of getting $TT=P\left(TT\right)$

=$\frac{numberoffavourableevents}{Totalspace\left(totalnumberofevents\right)}=\frac{1}{4}.$