Question

In a single pass rolling process using 410 mm diameter steel rollers, a strip of width 140 mm and thickness 8 mm undergoes 10% reduction of thickness. The angle of bite in radians is

• A. 0.006
• B. 0.031
• C. 0.062
• D. 0.600

Answer 1

The correct option is C 0.062

$\Delta H=D(1-cos\alpha )$

$cos\alpha =1-\frac{\Delta H}{D}=1-\frac{0.1\times 8}{410}=0.99804$

or $\alpha =co{s}^{-1}\left(0.99804\right)={3.58}^{\circ }$

$=0.0625$ radians