Question

In a single pass rolling process using 410 mm diameter steel rollers, a strip of width 140 mm and thickness 8 mm undergoes 10% reduction of thickness. The angle of bite in radians is

• A. 0.006
• B. 0.031
• C. 0.062
• D. 0.600

Answer 1

The correct option is C 0.062

d = 410 mm, R = 205 mm

W = 140 mm, $h_i$=8 mm,

$h_f=90$

Bite angle is gives as,

$cos\alpha =1-\frac{\Delta h}{2R}=1-\frac{(8-7.2)}{2\times 205}$

$cos\alpha =1-\frac{0.8}{410}=\frac{409.2}{410}$

$\alpha =co{s}^{-1}\left(\frac{409.2}{410}\right)={3.58}^{\circ }$

$={3.58}^{\circ }\times \frac{\pi }{{180}^{\circ }}$

= 0.0624 radians