Question

In a single pulse modulation scheme for $1-\varphi$ full bridge inverter, the amplitude of carrier wave and reference wave are 5 and 3 V respectively & input voltage to inverter is 115 V. The peak value of fundamental component of output voltage is

Answer 1

In a multiple pulse width modulation scheme, pulse width$=\left(\frac{2d}{N}\right)=(1-\frac{V_r}{V_c}).\frac{\pi }{N}$

$V_r$ = Amplitude of reference wave
$V_c$ = Amplitude of carrier wave
N = No. of pulse per half cycle

Here, N = 1

$2d=(1-\frac{3}{5})\times \pi$

$2d=0.4\times 180={72}^0$

The output voltage of $1-\varphi$ F.B.I., with single pulse modulation

$V_0=\sum _{n=1,3,5}^{\infty }\frac{4V_s}{n\pi }.\sin \frac{n\pi }{2}.\sin nd.\sin n\omega t$

$V_{01}=\frac{4\times 115}{\pi }\times \sin \frac{\pi }{2}\times \sin 36=86.06Volt$