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Question

In a single slit diffraction with λ=500nm and a lens of diameter 0.1 mm, width of central maxima, obtain on screen at a distance of 1 m will be

A
5mm
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B
1mm
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C
10mm
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D
2.5mm
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Solution

The correct option is D 10mm
Angle subtended by two minima at the slit in a single slit diffraction =α=2λw
where, w is the slit width.
Here the lens' diameter would act as slit width.
The width of central maxima is the distance between the two minima =dα
where, d is the distance between slit and screen =1 m
Thus, the width of central maxima =10 mm

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