Question

In a single throw of a pair of dice, the probability of getting the sum a perfect square is

• A. $\frac{1}{18}$
• B. $\frac{7}{36}$
• C. $\frac{1}{6}$
• D. $\frac{2}{9}$

Answer 1

The correct option is B $\frac{7}{36}$

Total number of outcomes is $36$.

Let $E$ be the event of getting the sum as perfect square.

Number of outcomes favourable to $E$ are $7$:

$(1,3),(2,2),(3,1),(3,6),(4,5),(5,4),(6,3)$

Probability of $E$ is number of outcomes favourable to $E$ divided by total number of outcomes that is $\frac{7}{36}$.

Hence, the probability of getting the sum as perfect square is $\frac{7}{36}$.