Question

In a single throw of die, find the probability of getting
(i) a number divisible by 2 or 3
(ii) a number divisible by 2 and 3
(iii) a number between 2 and 5
(iv) a number less than 7
(v) a number not prime.

Answer 1

i) Possible outcomes $=2,3,6=3$

P (i) $=\frac{3}{6}=\frac{1}{2}$

Total outcomes $=6$

ii) Possible outcomes $=6$

P (ii) $=\frac{1}{6}$

iii) Possible outcomes $=3,4$

p (iii) $=\frac{2}{6}=\frac{1}{3}$

iv) Possible outcomes $=1,2,3,4,5,6$

P (iv) $=\frac{6}{6}=1$

v) Possible outcomes $=2,1,4,6$

P (v) $=\frac{4}{6}=\frac{2}{3}$