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Question
In a single throw of pair of dice,what is the probability of getting the sum a perfect square?
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Solution
Total no. of outcomes = 36 Let E be the event of getting the sum as perfect square. No. of outcomes favourable to E = 7 { (1,3) (2,2) (3,1) (3,6) (4,5) (5,4) (6,3) } Probability of E = No. of outcomes favourable to E / Total No. of Outcomes = 7 / 36
Total no. of outcomes = 36
Let E be the event of getting the sum as perfect square.
No. of outcomes favourable to E = 7 { (1,3) (2,2) (3,1) (3,6) (4,5) (5,4) (6,3) }
Probability of E = No. of outcomes favourable to E / Total No. of Outcomes
= 7 / 36
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