Question

In a single throw of three dice, find the probability of getting (i) a total of 5 (ii) a total of at most 5.

Answer 1

Clearly, n(S)= $6^3=216$

(i) n(E)= 6 [ (1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)]

p(E)= $\frac{6}{216}=\frac{1}{36}$

(ii) n(E) = [(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)]

p(E)= $\frac{10}{216}=\frac{5}{108}$