In a single throw of two coins, find the progagilit of getting (i) both tails, (ii) at least 1 tail, (iii) at the most 1 tail.

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Solution

In a single throw of teo coins,
(i) Probalility of getting both tails = $\frac{1}{4}$
(ii) Probability of getting at least one tail $= \frac{3}{4}$ (iii) Probablity of getting at most one tail= $\frac{2}{4} = \frac{1}{2}$

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