Question

In a single throw of two dice, find the probability of getting a doublet of odd numbers.

• A. $\frac{1}{9}$
• B. $\frac{1}{18}$
• C. $\frac{1}{36}$
• D. $\frac{1}{12}$

Answer 1

Answer: (D)

$\frac{1}{12}$

Total number of exhaustive cases in a single throw of two dice$=6\times 6=36$

Doublets are obtained as $(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)$

Number of doublets of odd numbers$=3$

$\therefore$ Required probability$=\frac{3}{36}=\frac{1}{12}$.