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Question

In a single throw of two dice, find the probability of getting a doublet of odd numbers.

A
19
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B
118
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C
136
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D
112
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Solution

The correct option is C 112
Total number of exhaustive cases in a single throw of two dice=6×6=36
Doublets are obtained as (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)
Number of doublets of odd numbers=3
Required probability=336=112.

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