Question

In a single throw of two dice, find the probability of obtaining 'a total of $8$'.

Answer 1

We know that in a single throw of two dice, the total number of possible outcomes is $(6\times 6)=36$

Let S be the sample space. Then, $n\left(S\right)=36$

Let E = event of getting a total of 8. Then,

$E=\left\{\right(2,6),(3,5),(4,4),(5,3),(6,2\left)\right\}$ and, therefore, $n\left(E\right)=5$.

$\therefore$ P(getting a total of $8$) $=P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{5}{36}$.