Question

In a single throw of two dice, what is the probability of a double?

• A. $\frac{1}{6}$
• B. $\frac{5}{6}$
• C. $\frac{1}{9}$
• D. $\frac{1}{18}$

Answer 1

The correct option is A $\frac{1}{6}$

A 'double' means that both the dice show the same number on the upper most faces.

Therefore, the outcomes, favorable to this event are (1, 1), (2, 2), (3,3), (4,4), (5,5), (6,6)

Thus, the number of favorable cases = 6

$Hence,P\left(doublet\right)=\frac{6}{36}=\frac{1}{6}$