The correct option is A 56
Since, There are 36 elements in Sample space.
Let A be the event getting the same no. on both dice.
then A= {(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}
no. of elements in A = 6
∴ no. of elements that are not in A are = 36−6=30
∴ P( not getting the same number on both the dice) = 3036=56
∴ Option C is correct.