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Question

In a situation shown below, if the speed of the tip of the seconds hand is v m/s, find the magnitude of change in its velocity.


A
1.732v m/s
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B
1.414v m/s
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C
0.707v m/s
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D
v m/s
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Solution

The correct option is A 1.732v m/s
For one complete revolution of second's hand, θ=2π radians.
θ for 20 s=2π60×20=2π3 radians.

Thus, the magnitude of change in velocity is given by
|v2v1|=v22+v212v2v1 cos θ
Given v1=v2=v
So, |v2v1|=v2+v22v2 cos2π3=3v=1.732v m/s

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