Question

In a slab rolling operation, the maximum thickness reduction $\left(\Delta h_{max}\right)$ is given by $\Delta h_{max}={\mu }^{2}R,$ where R is the radius of the roll and $\mu$ is the coefficient of friction between the roll and the sheet. If $\mu =0.1$, the maximum angle subtended by the deformation zone at the centre of the roll (bite angle in degree) is .

Answer 1

$\Delta h_{max}={\mu }^{2}R$

$\Delta h=D(1-cos\alpha )$

$\Rightarrow {\mu }^{2}R=D(1-cos\alpha )$

$\Rightarrow (0.1{)}^2=2(1-cos\alpha )$

or $\alpha ={5.73}^{\circ }$