In a sliding window ARQ scheme, the transmitter's window size is N and receiver's window size is M. The minimum number of distinct sequence numbers required to ensure correct operation of the ARQ scheme is
A
max (M, N)
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B
M + N
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C
MN
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D
min (M, N)
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Solution
The correct option is B M + N In sliding window protocol :
Minimum number of sequence number = M + N
Since at any time number of unacknowledged frames are M at receiver and same time N packets are transmitted by sender.
So, M+N ≤ minimum sequence number.