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Question

In a solid AB having NaCl structure, A atoms occupy the corners of the cubic unit cell. If all the face-centred atoms along one of the axes are removed, then the resultant stoichiometry of the solid is:

A
AB2
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B
A2B
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C
A4B3
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D
A3B4
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Solution

The correct option is D A3B4
As given, AB has NaCl - type structure (fcc systems).

Number of A atoms
=8 (corner) ×18 (per corner share) +6 (faces) ×12 (per face center share) =1+3=4 per unit cell

Number of B atoms
=12 (edges) ×14 (per edges share) +1 (body center) =1+3=4 per unit cell

Number of A atoms removed (face centered atom of one axis)
=2 (faces) ×12 (per face centre share) =1 per unit cell

Number of A atoms left =41=3 per unit cell

Therefore, the formula is A3B4.

Hence, option is D.

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