In a solid AB having the NaCl structure, A atoms occupy the corners of cube unit cell. If all the face centred atoms along one of the axes are removed, then resultant stoichiometry of the solid is
1.AB2
2.A2B
3.A4B3
4.A3B4
There were 6 A atoms on the face-centres removing face-centred atoms
along one of the axes means removal of 2 A atoms.
Now, number of A atoms per unit cell
Number of B atoms per unit cell
Hence the resultant stoichiometry is A3B4.
Hope it makes you clear.