In a solution, the concentration of $C a C l_{2}$ is $5 M$ and that of $M g C l_{2}$ is $5 M$ . The specific gravity of solution is $1.05$ . Calculate the concentration of $C l^{-}$ in the solution in terms of its molarity.

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Solution

1 molecule of $C a C l_{2}$ has $2 m o l e s C l^{-}$
$\Rightarrow 5 M C a C l_{2} = 2 \times 5 = 10 M C l^{-}$
1 molecule of $M g C l_{2}$ has $2 m o l e s C l^{-}$
$\Rightarrow 5 M M g C l_{2} = 2 \times 5 = 10 M C l^{-}$
Total concentration of $C l^{-} = 20 M$

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In a solution, the concentration of CaCl2 is 5M and that of MgCl2 is 5M. The specific gravity of solution is 1.05 . Calculate the concentration of Cl− in the solution in terms of its molarity.

1 molecule of CaCl2 has 2 moles Cl− ⇒5M CaCl2=2×5=10M Cl− 1 molecule of MgCl2 has 2 moles Cl− ⇒5M MgCl2=2×5=10M Cl− Total concentration of Cl−=20M

In a solution, the concentration of $C a C l_{2}$ is $5 M$ and that of $M g C l_{2}$ is $5 M$ . The specific gravity of solution is $1.05$ . Calculate the concentration of $C l^{-}$ in the solution in terms of its molarity.

1 molecule of $C a C l_{2}$ has $2 m o l e s C l^{-}$
$\Rightarrow 5 M C a C l_{2} = 2 \times 5 = 10 M C l^{-}$
1 molecule of $M g C l_{2}$ has $2 m o l e s C l^{-}$
$\Rightarrow 5 M M g C l_{2} = 2 \times 5 = 10 M C l^{-}$
Total concentration of $C l^{-} = 20 M$