In a sphere made of an alloy, copper and tin are in the ratio $86 : 14$ . In a sphere made of another alloy, copper and zinc are in the ratio $58 : 42$ . Find the ratio of tin and zinc in the sphere made by melting the two spheres.

1 : 3

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2 : 3

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3 : 4

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3 : 5

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Solution

The correct option is B $1 : 3$
Let the weight sphere be of x each.
Hence, amount of $t i n = 14 x, z i n c = 42 x$
Ratio: $\frac{14 x}{42 x} = \frac{1}{3}$

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In a sphere made of an alloy, copper and tin are in the ratio 86:14. In a sphere made of another alloy, copper and zinc are in the ratio 58:42. Find the ratio of tin and zinc in the sphere made by melting the two spheres.

The correct option is B 1:3Let the weight sphere be of x each.Hence, amount of tin=14x,zinc=42xRatio: 14x42x=13

In a sphere made of an alloy, copper and tin are in the ratio $86 : 14$ . In a sphere made of another alloy, copper and zinc are in the ratio $58 : 42$ . Find the ratio of tin and zinc in the sphere made by melting the two spheres.

The correct option is B $1 : 3$
Let the weight sphere be of x each.
Hence, amount of $t i n = 14 x, z i n c = 42 x$
Ratio: $\frac{14 x}{42 x} = \frac{1}{3}$