In a steady state of thermal conduction- temperature of the ends A and B of a 20 cm long rod are 100- C and 0- C respectively- What will be the temperature of the rod at a point at a distance of 6 cm from the end A of the rodA- -30- CB- None of the aboveC -70- CD- 5- C

The correct option is C In steady state, temperature gradient = constant ⇒(θ _A θ _x)/6=(θ _A θ _B)/20⇒ ( 100 θ _x )=6/20× ( 100 0 ) ⇒θ _x=70^∘C ...

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Standard VII

Physics

Conduction Law

In a steady s...

Question

In a steady state of thermal conduction, temperature of the ends A and B of a 20 cm long rod are $100^{\circ}$ C and $0^{\circ}$ C respectively. What will be the temperature of the rod at a point at a distance of 6 cm from the end A of the rod

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None of the above

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Solution

The correct option is B
In steady state, temperature gradient = constant

$\Rightarrow \frac{(θ_{A} - θ_{x})}{6} = \frac{(θ_{A} - θ_{B})}{20} \Rightarrow (100 - θ_{x}) = \frac{6}{20} \times (100 - 0)$
$\Rightarrow θ_{x} = 70^{\circ} C$

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In a steady state of thermal conduction, temperature of the ends A and B of a 20 cm long rod are 100∘ C and 0∘ C respectively. What will be the temperature of the rod at a point at a distance of 6 cm from the end A of the rod

The correct option is B In steady state, temperature gradient = constant ⇒(θA−θx)6=(θA−θB)20⇒(100−θx)=620×(100−0) ⇒θx=70∘C

In a steady state of thermal conduction, temperature of the ends A and B of a 20 cm long rod are $100^{\circ}$ C and $0^{\circ}$ C respectively. What will be the temperature of the rod at a point at a distance of 6 cm from the end A of the rod

The correct option is B
In steady state, temperature gradient = constant

$\Rightarrow \frac{(θ_{A} - θ_{x})}{6} = \frac{(θ_{A} - θ_{B})}{20} \Rightarrow (100 - θ_{x}) = \frac{6}{20} \times (100 - 0)$
$\Rightarrow θ_{x} = 70^{\circ} C$