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Question

In a steam power plant, superheated steam at 10MOa and 500oC, is expanded isentropically in a turbine untiil it becomes a saturated vapour. it is then reheated at constant pressure to 500oC. The steam is next expanded isentropically in another trubine until it reaches the condenser pressure of 20kPa. Relevant properties of steam are given in the following two tables. The work done by both the turbines together is
kJ/kg (roundoff to the nearest integer).
Superheated Steam Table:
Presure,p
(MPa)
Temp, p
(oC)
Enthalpy, h
(kJ/kg)
Entropy,s
(kJ.kg.K)
10 500 3373.6 6.5965
1 500 3478.4 7.7621

Saturated Steam Table:

​​​​​​​
  1. 1512.95

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Solution

The correct option is A 1512.95
Given data:
at 10MPa,500oC,h1=3373.6kJ/kg
at 1MPa,500oC,h3=3478.4,kJ/kg
s3=7.7621kJ/kgK
at1MPa,h2=hg=2778.1,kJ/kg


s3=s4=[sf+x(xgsf)]@20kPa
s3=7.7621
=0.319+x+(7.90850.8319)
x4=0.9793
at 20kPa,h4=hf+x4×(hghf)
2560.91kJ/kg
workdone by turbine,
WT=(h1h2)+(h3=h4)
=1512.95kJ/kg

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